In the given circuit, with steady current, the potential drop across the capacitor must be

Options

A. V
B. `V//2`
C. `V//3`
D. `2V//3`

Answer

C

Explanation

(c) There will be no current flowing in branch BE in steady
conditon.
Let I be the current flowing in the loop ABCDEFA.
Applying Kirchoff's law in the loop moving in
anticlockwise direction starting from C.
`+2V - I(2R) - I(R) - V = 0`
`:. V = 3IR`
`rArr I = V//3R` .....(1)
Applying Kirchoff's law in the loop moving in
moving in anticlockwise direction starting from B.

`+V+V_(cap) -IR - V = 0` (where `V_(cap)` is the p.d. across
capacitor).
`:. V_(cap) = IR = (V)/(3R) xx R = V/3`.