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In the shown arrangement of the experiment of the meter bridge if AC corroesponding to null deflection of galvanometer is x, what would be its value if the radius of the wire AB is doubled?
.

A

x

B

`x//4`

C

4x

D

2x

Text Solution

Verified by Experts

The correct Answer is:
A
(a)
At null point
`R_1/R_2 = R_3/R_4 = x/(100-x)`
If radius of the wire is doubled, then the resistanceof
AC will change and also the resistance of CB will
change. But since `R_1/R_2` does not change so, `R_3/R_4` should
also not change at null point. Therefore the point C
does not change.
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