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Incandescent bulbs are designed by keeping in mind that the resistance of their filament increases with the increase in temperature. If at room temperature, `100W, 60W and 40W` bulbs have filament resistances `R_(100), R_(60) and R_(40)`, respectively, the relation between these resistances is

A

`1/R_(100) = 1/R_(40) + 1/R_(60)`

B

`R_(100) = R_(40) + R_(60)`

C

`R_(100)gtR_(60)gtR_(40)`

D

`1/R_(100) gt 1/R_(60) gt 1/R_(40)`

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The correct Answer is:
To solve the problem, we need to understand the relationship between power, voltage, and resistance in incandescent bulbs. The power \( P \) of a bulb can be expressed using Ohm's law and the formula for electrical power: \[ P = \frac{V^2}{R} \] Where: - \( P \) is the power of the bulb, - \( V \) is the voltage across the bulb, - \( R \) is the resistance of the bulb. ### Step 1: Write the equations for each bulb For the 100W, 60W, and 40W bulbs, we can write the following equations based on the power formula: 1. For the 100W bulb: \[ P_{100} = \frac{V^2}{R_{100}} \implies R_{100} = \frac{V^2}{100} \] 2. For the 60W bulb: \[ P_{60} = \frac{V^2}{R_{60}} \implies R_{60} = \frac{V^2}{60} \] 3. For the 40W bulb: \[ P_{40} = \frac{V^2}{R_{40}} \implies R_{40} = \frac{V^2}{40} \] ### Step 2: Relate the resistances Now we can relate the resistances \( R_{100}, R_{60}, \) and \( R_{40} \): From the equations derived above, we have: \[ R_{100} = \frac{V^2}{100}, \quad R_{60} = \frac{V^2}{60}, \quad R_{40} = \frac{V^2}{40} \] ### Step 3: Take the reciprocal of the resistances To compare the resistances, we can take the reciprocal of each: \[ \frac{1}{R_{100}} = \frac{100}{V^2}, \quad \frac{1}{R_{60}} = \frac{60}{V^2}, \quad \frac{1}{R_{40}} = \frac{40}{V^2} \] ### Step 4: Establish the relationship From the above, we can establish the relationship between the reciprocals of the resistances: \[ \frac{1}{R_{100}} > \frac{1}{R_{60}} > \frac{1}{R_{40}} \] This implies: \[ R_{100} < R_{60} < R_{40} \] ### Conclusion Thus, the relationship between the resistances of the bulbs is: \[ R_{100} < R_{60} < R_{40} \]

To solve the problem, we need to understand the relationship between power, voltage, and resistance in incandescent bulbs. The power \( P \) of a bulb can be expressed using Ohm's law and the formula for electrical power: \[ P = \frac{V^2}{R} \] Where: - \( P \) is the power of the bulb, ...
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