As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current `I_(P)` (as seen by E) and an induced current `I_(Q1)` flows in Q. The switch remains closed for a long time. when S is opened, a current `I_(Q2)` flows in Q. Then the direction `IQ_(1) and IQ_(2)` (as seen by E) are

Options

A. respectively clockwise and anti-clockwise
B. both clockwise
C. both anti-clockwise
D. respectively anti-clockwise and clockwise

Answer

D

Explanation

When switch S is closed, a magnetic field is set-up in the space around P. The field lines threading Q increases in the direction from right to left. According to Lenz's law. `(I_(Q_1))` will flow so as to oppose the cause and flow in anticlockwise direction as seen by E. Reverse is the case wheb S is opened. `(I_(Q_2))` will be clockwise.