A conduting square loop of side L and resistnce R moves in its plane with a uniform velocity v perpendicular to one of its sides. A magnitude induction B constant in time and space, pointing perpendicular and into to plane at the loop exists every with half the loop outside the field, as shown in figure. The induced emf is

Options

A. zero
B. RvB
C. `vBL//R`
D. `vBL`

Answer

D

Explanation

(d) The induced emf is
`e=(-d phi)/(dt)=-(d(vec(B).vec(A))/(dt=(-d(BA cos 0^(@)))/(dt)`

`:. E=-B(dA)/(dt)=-B(d(l xx x))/(dt)=-Bl(dx)/(dt)=-Blv`.