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When the current changes from +2A to -2A...

When the current changes from +2A to -2A in 0.5 second an emf of 8V is induced in a coil. The coefficient of selfinduction of the coil is

A

0.2H

B

0.4H

C

0.8H

D

0.1H

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `e=-(Delta phi)/(Delta t)=(-Delta(LI))/(Delta t)=-L(Delta I)/(delta t)`
`:. |e|=L(delta I)/(delta t) implies 8=Lxx4/0.05`
`+. L=(8xx0.05)/4=0.1H`.
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