Home
Class 12
PHYSICS
In an AC generator, a coil with N turns,...

In an AC generator, a coil with N turns, all of the same area A and total resistance R, rotates with frequency `(omega)` in a magnetic field B. The maximum value of emf generated in the coils is

A

`N.A.B.R.omega`

B

`N.A.B`

C

`N.A.B.R`

D

`N.A.B.omega`

Text Solution

AI Generated Solution

The correct Answer is:
To find the maximum value of the electromotive force (emf) generated in an AC generator, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Components**: - The AC generator consists of a coil with \( N \) turns, area \( A \), total resistance \( R \), rotating in a magnetic field \( B \) with angular frequency \( \omega \). 2. **Induced EMF Formula**: - The induced emf (\( E \)) in the coil can be derived from Faraday's law of electromagnetic induction, which states: \[ E = -\frac{d\Phi}{dt} \] where \( \Phi \) is the magnetic flux. 3. **Magnetic Flux Calculation**: - The magnetic flux (\( \Phi \)) through one turn of the coil is given by: \[ \Phi = B \cdot A \cdot \cos(\theta) \] where \( \theta \) is the angle between the magnetic field and the normal to the coil's surface. As the coil rotates, \( \theta \) changes with time, and we can express it as: \[ \theta = \omega t \] Thus, the magnetic flux becomes: \[ \Phi = B \cdot A \cdot \cos(\omega t) \] 4. **Differentiating the Flux**: - To find the induced emf, we differentiate the magnetic flux with respect to time: \[ \frac{d\Phi}{dt} = \frac{d}{dt}(B \cdot A \cdot \cos(\omega t)) = -B \cdot A \cdot \omega \sin(\omega t) \] - Therefore, the induced emf is: \[ E = -N \frac{d\Phi}{dt} = -N \left(-B \cdot A \cdot \omega \sin(\omega t)\right) = N B A \omega \sin(\omega t) \] 5. **Finding Maximum EMF**: - The maximum value of the induced emf occurs when \( \sin(\omega t) \) is at its maximum value, which is 1. This occurs when \( \omega t = \frac{\pi}{2} \) (or 90 degrees). - Thus, the maximum emf (\( E_{\text{max}} \)) is given by: \[ E_{\text{max}} = N B A \omega \] ### Final Answer: The maximum value of the emf generated in the coils is: \[ E_{\text{max}} = N B A \omega \]

To find the maximum value of the electromotive force (emf) generated in an AC generator, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Components**: - The AC generator consists of a coil with \( N \) turns, area \( A \), total resistance \( R \), rotating in a magnetic field \( B \) with angular frequency \( \omega \). 2. **Induced EMF Formula**: ...
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise JEE Main And Advanced|129 Videos
  • ELECTROSTATICS

    SUNIL BATRA (41 YEARS IITJEE PHYSICS)|Exercise Comprehension Based Questions|2 Videos

Similar Questions

Explore conceptually related problems

A coil of N turns and area A is rotated at the rate of n rotations per second in a magnetic field of intensity B, the magnitude of the maximum magnetic flux will be __

The number of turns in the coil of an ac genrator is 5000 and the area of the coil is 0.25m^(2) . The coil is rotate at the rate of 100 "cycles"//"sec" in a magnetic field of 0.2W//m^(2) . The peak value of the emf generated is nearly

A coil of N turns and mean cross-sectional area A is rotating with uniform angular velocity omega about an axis at right angle to uniform magnetic field B. The induced emf E in the coil will be

An armature coil consists of 20 turns of wire each of area A = 0.09 m^(2) and total resistance 15.0 ohm. It rotates in a magnetic field of 0.5 T at a constant frequency of (150)/(pi) Hz . Calculate the value of (i) maximum and (ii) average induced e.m.f. produced in the coil.

In an ac generator, the number of turns in the coil is 2000 and the area of coil is 0.2 m^(2) . If the coil is rotated at an angular frequency of 400 S^(-1) in a magnetic field of 0.5 T , then what is the peak value of induced emf ?

An AC generator consists of a coil of 200 turns and area of 5 m^(2) rotating at a constant angular speed of 60 rad /s in a uniform magnetic field of 0.05 T. The resistance of the coil is 400 omega . Calculate maximum current drawn from the generator .

SUNIL BATRA (41 YEARS IITJEE PHYSICS)-ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENT-JEE Main And Advanced
  1. Which of the following units denotes the dimension (ML^(2))/(Q^(2)), w...

    Text Solution

    |

  2. In a series resonant LCR circuit the voltage across R is 100 volts and...

    Text Solution

    |

  3. In an AC generator, a coil with N turns, all of the same area A and to...

    Text Solution

    |

  4. The flux linked with a coil at any instant 't' is given by phi = 10t^(...

    Text Solution

    |

  5. An inductor (L = 100 mH), a resistor (R = 100 (Omega)) and a battery (...

    Text Solution

    |

  6. In an a.c. Circuit the voltage applied is E=E(0) sin (omega)t. The res...

    Text Solution

    |

  7. An ideal coil of 10H is connected in series with a resistance of 5(Ome...

    Text Solution

    |

  8. Two coaxial solenoids are made by winding thin insulated wire over a p...

    Text Solution

    |

  9. An inductor of inductance L=400 mH and resistor of resistance R(1) = 2...

    Text Solution

    |

  10. A rectangular loop has a sliding connector PQ of length l and resistan...

    Text Solution

    |

  11. In the circuit shown below, the key K is closed at t = 0. The current ...

    Text Solution

    |

  12. In a series LCR circuit R= 200(Omega) and the voltage and the frequenc...

    Text Solution

    |

  13. A boat is moving due east in a region where the earth's magnetic field...

    Text Solution

    |

  14. A fully charged capacitor C with initial charge q(0) is connected to a...

    Text Solution

    |

  15. A resistor 'R' and 2(mu)F capacitor in series is connected through a s...

    Text Solution

    |

  16. A coil is suspended in a uniform magnetic field, with the plane of the...

    Text Solution

    |

  17. A metallic rod of length 'l' is tied to a string of length 2l and made...

    Text Solution

    |

  18. A circular loop of radius 0.3 cm lies parallel to amuch bigger circula...

    Text Solution

    |

  19. In an LCR circuit as shown below both switches are open initially. Now...

    Text Solution

    |

  20. An inductor (L = 100 mH), a resistor (R = 100 (Omega)) and a battery (...

    Text Solution

    |