In an a.c. Circuit the voltage applied is `E=E_(0) sin (omega)t`. The resulting current in the circuit is `I=I_(0)sin((omega)t-(pi/2))`. The power consumption in the circuit is given by

Options

A. `P=sqrt(2)E_(0)I_(0)`
B. `P=(E_(0)I_(0))/(sqrt(2))`
C. P=zero
D. `P=(E_(0)I_(0))/(2)`

Answer

C

Explanation

(c) We know that power consumed i a.c. Circuit is given by `P=E_(rms) I_(rms) cos phi`
Here, `E=(E_0) sin omega t`
`I=(i_0)sin(omega t-(pi)/(2))
Which implies that the phase diffenence, `(phi)=(pi)/(2)`
`:. P=E_(rms).I_(rms).cos(pi)/(2)=0 {:. cos (pi)/(2)=0)`.