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A fully charged capacitor C with initial...

A fully charged capacitor C with initial charge `q_(0)` is connected to a coil of self inductance L at t=0. The time at which the energy is stored equally between the electric and the magnetic fields is

A

`(pi)/(4)sqrt(LC)`

B

`2 pi sqrt(LC)`

C

`sqrt(LC)`

D

`pisqrt(LC)`

Text Solution

Verified by Experts

The correct Answer is:
A

(a) Energy stored in magnetic field `=1/2 Li^(2)`
Energy stored in electric field `=1/2 (q^2)/(C)`
`:. 1/2 (Li^(2))=1/2(q^2)/(C)` Also `q=(q_0) cos (omega)t and (omega)=(1)/(sqrt(LC))`
on solving `t=(pi)/(4)sqrt(LC)`.
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