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An inductor (L = 100 mH), a resistor (R ...

An inductor `(L = 100 mH)`, a resistor `(R = 100 (Omega))` and a battery `(E = 100 V)` are initially connected in series as shown in the figure. After a long time the battery is disconnected after short circuiting the point A and B. The current in the circuit 1 ms after the short circuit is

A

`(e)/(1-e)`

B

`1`

C

`-1`

D

`(1-e)/(e)`

Text Solution

Verified by Experts

The correct Answer is:
C
(c) Applying Kirchhoff's law of voltage in closed loop
`-V_(R)-V_(C)=0implies (V_R)/(V_C)=-1`
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