Two charges `+3.2 xx 10^(-19) C` and `-3.2 xx 10^(-9) C` kept `2.4 Å` apart forms a dipole. If it is kept in uniform electric field of intensity `4 xx 10^(5) vol//m` then what will be its electrical energy in equilibrium ?

Two charges +3.2 xx 10^(-19)C and -3.2 xx 10^(-19)C placed at 2.4A^(@) apart form an electric dipole. It is placed in a uniform electric field of intensity 4 xx 10^(5) volt/m. The electric dipole- moment is

Two charges +3.2xx10^(-19) and -3.2xx10^(-19)C placed at 2.4A apart from an electric dipole. It is placed in a uniform electric field of intensity 4xx10^(5) "volt"//m . The electric dipole moment is

Two charges +3.2xx10^-19C and -3.2xx10^-19C are placed 2.4 A apart from an electric dipole.it is placed in a uniform electric field of intensity 4xx10^5 V/m . The electric dipole moment is

Two charges +3.2xx10^(-19)C and -3.2xx10^(-19)C placed 2.4 A^(0) apart form an electric dipole. It is placed in a uniform electric field of intensity 4xx10^(5)V//m the work done to rotate the electric dipole form the equilibrium position by 180^(@) is

Two point charges of 3.2 xx 10^-19 C and -3.2 xx 10^-19 C are separated from each other by 2.4 xx 10^-10 m . The dipole is situated in a uniform electric field of intensity 4 xx 10^5 Vm^-1 . Calculate the work done in roating the dipole by 180^(@) .

Two point charges of 3.2 xx 10^-19 C and -3.2 xx 10^-19 C are separated from each other by 2.4 xx 10^-10 m . The dipole is situated in a uniform electric field of intensity 4 xx 10^5 Vm^-1 . Calculate the work done in roating the dipole by 180^(@) .

Two charges +2xx10^(-9) C and -8xx10^(-9) C are placed 0.3 M apart in air. Find the point or p[oints where the electric field and potential is zero.