ABCDE is a cyclic pentagon with centre of its circumcircle at point O such that AB=BC=CD and angle ABC=120 degree. calculate: (i) angle BEC (ii) angle BED

ABCDE is a cyclic pentagon with centre of its circumcircle alt point O such that AB=BC=CD and angle ABC=120^(@) Calculate (i) /_BEC (ii) /_BED

The centre of circumcircle of a quadrilateral ABCD is O. If AB = BC and angleBAC=40^(@) then find angle angleADC .

A circle, with centre O, circumscribs a pentagon ABCDE. IF AB- BC= CD and angle BCD = 126^(@), find: angle AEB

A circle, with centre O, circumscribs a pentagon ABCDE. IF AB- BC= CD and angle BCD = 126^(@), find: angle AED

A circle, with centre O, circumscribs a pentagon ABCDE. IF AB- BC= CD and angle BCD = 126^(@), find: angle AOC

In triangle ABC, O is the orthocenter and angle BOC is 120^(@) . Calculate angle BAC.

ABCD is a cyclic trapezium such that AD || BC. If angle ABC=70^(@) , then the value of angleBCD is :

In the given figure , AD is a diameter O is the centre of the circle AD is parallel to BC and angle CBD = 32 ^(@) (i) angle OBD (ii ) angle AOB (iii) angle BED

ABCDE is a pentagon in which AB = AE, BC = ED and angle ABC = angle AED. Prove that AC= AD (ii) angle BCD= angle EDC

ABCD is a cyclic quadrilateral in which AB is parallel to DC and AB is a diameter of the circle. Given angle BED = 65^(@) , Calculate (i) angle DAB (ii) angle BDC