5*[[2,-3,3],[2,2,3],[3,-2,2]]

If A = [[2/3,1,5/3],[1/3,2/3,4/3],[7/3,2,2/3]] and B = [[2/5,3/5,1],[1/5,2/5,4/5],[7/5,6/5,2/5]] , then compute 3A-5B

If A=[[-1,5],[-3,2]] , then adj A= (A) [[2,3],[-5,-1]] (B) [[1,-5],[3,-2]] (C) [[2,-5],[3,-1]] ,(D) [[-2,5],[-3,1]]

If A=[[2/3, 1,5/3],[1/3, 2/3, 4/3],[7/3, 2, 2/3]] and B=[[2/5, 3/5, 1],[1/5, 2/5, 4/5],[7/5, 6/5, 2/5]] then compute 3A-5B

Construct a frequency table for the following: 3,2,5,4,1,3,2,2,5,3,1,2,1,1,2,2,3,4,5,3,1,2,3.

The value of [[1],[-2],[3]][[4,5,2]][[2],[-3],[5]] is

.The value of [[1],[-2],[3]][[4,5,2]][[2],[-3],[5]] is

If A=[[2/3, 1, 5/3],[ 1/3, 2/3, 4/3] ,[7/3, 2, 2/3]] and B=[[2/3, 3/5, 1],[ 1/5, 2/5, 4/5],[ 7/3, 6/5, 2/5]] , then compute 3A - 5B .

A company manufactures car batteries of a particular type. The lives (in years) of 40 such batteries were recorded as follows : {:(2.6,3.0,3.7,3.2,2.2,4.1,3.5,4.5,3.5,2.3,3.2),(3.4,3.8,3.2,4.6,3.7,2.5,4.4,3.4,3.3,2.9,3.0),(4.3,2.8,3.5,3.2,3.9,3.2,3.2,3.1,3.7,3.4,4.6),(3.8,3.2,2.6,3.5,4.2,2.9,3.6,,,,):} Construct a grouped frequency distribution table for this data, using class intervals of size 0.5 starting form the intervals 2-2.5