`(x^(3)-1)` can be fa ctorised as

The function f:A rarr R,f(x)=(1)/(sqrt(4x^(2)-1))+ln(x(x^(2)-1)) , f:A rarr R,f(x)=(1)/(sqrt(4x^(2)-1))+ln(x(x^(2)-1)) is (Here A is the largest possible domain of the given function

Let A={x in R:x<=1} and f:A rarr A be defined as f(x)=x(2-x). Then ,f^(-1)(x) is

Using division of polynomials state whether x+6 i s fa c tor of x^2-x-42 4x-1 i s a fa c tor of 4x^2-13 x-12 2y-5 i s fa c tor of 4y^4-10 y^3 10^2+30 y-15 3y^2+5 i s fa c tor of 6y^5+15^4+16^3+4y^2+10 y-35

Let the solution set of the inequation n(sin x-(1)/(2))(sin x-(1)/(sqrt(2)))<=0in[(pi)/(2),pi] be A and let solution set of equation sin^(-1)(3x-4x^(3))=3sin^(-1)x be B. Now define a function f:A rarr B.

Let A={1,2,3},B={5,6,7} and f:A to B be a function defined as f={(1,6),(2,5),(3,7)} Then f is :

Let the solution set of the inequation n(sinx-1/2)(sinx-1/(sqrt(2)))lt=0 in [pi/2,pi] be A and let solution set of equation sin^-1(3x-4x^3)=3sin^-1x be B. Now define a function f:A->B.

Let the solution set of the inequation n(sinx-1/2)(sinx-1/(sqrt(2)))lt=0 in [pi/2,pi] be A and let solution set of equation sin^-1(3x-4x^3)=3sin^-1x be B. Now define a function f:A->B.

Let the solution set of the inequation n(sinx-1/2)(sinx-1/(sqrt(2)))lt=0 in [pi/2,pi] be A and let solution set of equation sin^-1(3x-4x^3)=3sin^-1x be B. Now define a function f:A->B.

Let A=R-{3},B=R-{1} " and " f:A rarr B defined by f(x)=(x-2)/(x-3) . Is 'f' bijective? Give reasons.

Let A=R-{3},B=R-{1} " and " f:A rarr B defined by f(x)=(x-2)/(x-3) . Is 'f' bijective? Give reasons.