The axes are translated so that the new equation of the circle `x^2+y^2-5x+2y-5=0` has no first degree terms and the new equation `x^2+y^2=lambda/4`, then find the value of `lambda`

The axes are translated to a point P so as to remove the first degree terms of the equation 2x^(2) + 3y^(2) - 12 x + 12y + 24 = 0 then P =

Find the value of lambda so that the line 3x-4y= lambda may touch the circle x^2+y^2-4x-8y-5=0

Find the value of lambda so that the line 3x-4y= lambda may touch the circle x^2+y^2-4x-8y-5=0

Find the point to which the axes are to be translated to eliminate x and y terms (remove first degree terms) in the equation 2x^(2)+4xy+5y^(2)-4x-22y+7 = 0.

Find the point to which the axes are to be translated to eliminate x and y terms (remove first degree terms) in the equation 2x^(2)+4xy+5y^(2)-4x-22y+7 = 0.

Find the point to which the axes are to be translated to eliminate x and y terms (remove first degree terms) in the equation 2x^(2) + 4xy + 5y^(2) - 4x - 22y + 7 = 0

If the equation x^(2) - y^(2) - 2x+2y+lambda =0 represents a degenerate conic then find the value of lambda .

By eliminating the constant in the following equation x^(2)-y^(2)=c(x^(2)+y^(2))^(2) its differential equation is y'=(x(lambda y^(2)-x^(2)))/(y(lambda x^(2)-y^(2))) then find the value of lambda

The point to which the axes be should translated to eliminate first degree terms in the equation x^(2)+y^(2)+z^(2)-2x-4y+2z-3=0

Choose a new origin so that the equation 2x^(2)+7y^(2)+8x-14y+15 = 0 may be translated to the which the first degree terms be missing. Find the transformed equation also.