- A small compass needle of magnetic moment M and moment of inertia I is free to oscillate in a magnetic field B. It is slightly disturbed from its equilibrium position and then released. Show that it executes simple harmonic motion. Hence, write the expression for its time period. Delhi 2011C

A small compass needle of magnetic moment .m. is free to turn about an axis perpendicular to the direction of uniform magnetic field .B.. The moment of inertia of the needle about the axis is .I.. The needle is slightly disturbed from its stable position and then released. Prove that it executes simple harmonic motion. Hence deduce the expression for its time period.

A small compass needle of magnetic moment M is free to turn about an axis perpendicular to the direction of uniform magnetic field B. The moment of inertia of the needle about the axis is I. The needle is slightly displaced from its stable position and then released. Prove that it executes simple harmonic motion. Hence deduce the expression for its time period.

A dipole of dipole moment P and moment of inertia I is placed in an unifrom electric filed vec(E) . If it is displaced slighty from its stable equilibrium position , then the period of the oscillation of dipole is .

Show that for a small oscillations the motion of a simple pendulum is simple harmonic. Derive an expression of its time period.

A magnet of magnetic moment M and having moment of inertia I , is suspended to orient freely in the horizontal plane under the influence of earth's magnetic field . If it is slightly disturbed , the time period is given by

A magnet of magnetic moment M and having moment of inertia I , is suspended to orient freely in the horizontal plane under the influence of earth's magnetic field . If it is slightly disturbed , the time period is given by

A bar magnet of magnetic moment M is suspended in a uniform magnetic field (B). The work done to rotate 180^@ from its equlibrium position will be —