In a triangle `A B C` , the bisectors of angles `Ba n dC` lies along the lines `x=ya n dy=0.` If `A` is `(1,2)` , then the equation of line `B C` is (a) `2x+y=1` (b) `3x-y=5` (c) `x-2y=3` (d) `x+3y=1`

In a triangle A B C , the bisectors of angles Ba n dC lies along the lines x=y a n d y=0. If A is (1,2) , then the equation of line B C is

In a triangle ABC ,the bisectors of angles BandC lies along the lines x=y and y=0 . If A is (1,2) ,then the equation of line BC is (a) 2x+y=1 (b) 3x-y=5 (c) x-2y=3 (d) x+3y=1

Equation of the bisector of angle B of the triangle ABC is y=x. If A is (2,6) and B is (1,1); equation of side BC is (A)2x+y-3=0 (B) x-5y+4=0 (C) x-6y+5=0 (D) none of these

Equation of the bisector of angle B of the triangle ABC is y = x . If A is (2,6) and B is (1, 1) ; equation of side BC is (A) 2x + y - 3 = 0 (B) x-5y+ 4 =0 (C) x- 6y + 5 = 0 (D) none of these

A B C is a variable triangle such that A is (1, 2), and Ba n dC on the line y=x+lambda(lambda is a variable). Then the locus of the orthocentre of "triangle"A B C is x+y=0 (b) x-y=0 x^2+y^2=4 (d) x+y=3

A B C is a variable triangle such that A is (1, 2), and Ba n dC on the line y=x+lambda(lambda is a variable). Then the locus of the orthocentre of "triangle"A B C is x+y=0 (b) x-y=0 x^2+y^2=4 (d) x+y=3

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0

A B C is a variable triangle such that A is (1,2) and B and C lie on line y=x+lambda (where lambda is a variable). Then the locus of the orthocentre of triangle A B C is (a) (x-1)^2+y^2=4 (b) x+y=3 (c) 2x-y=0 (d) none of these