. For the circuit shown in the figure the rms value of voltages across R and coil are E, and E,, respectively. L.r R Resistor Coil e = E, sinot eme=E

For the circuit shown in the figure the rms value of voltage across R and coil are E_(1) and E_(2) respectively. The power (thermal) developed across the coil is

In the series L-C-R circuit shown in the figure, the rms voltage across the resistor and inductor are 400 V and 700 V respectively. If the applied voltage is E=500sqrt(2)sin(omega t) , then the peak voltage across the capacitor is

In the series L-C-R circuit shown in the figure, the rms voltage across the resistor and inductor are 400 V and 700 V respectively. If the applied voltage is E=500sqrt(2)sin(omega t) , then the peak voltage across the capacitor is

In the given circuit the R.M.S values of voltages across the capacitor C, inductor L and resistor R_(1) are 12V, 10V and 5 V respectively. Then the peak voltage across R_(2) is

In the given circuit the R.M.S values of voltages across the capacitor C, inductor L and resistor R_(1) are 12V, 10V and 5 V respectively. Then the peak voltage across R_(2) is

In the circuit, as shown in the figure, if the value of R.M.S current is 2.2 ampere, the power factor of the box is (E = 220 V)

In the circuit shown in figure find: a. the current in the 3.00 Omega resistor,b. the unknown emfs E_1 and E_2 and c the resistance R .

In the circuit shown in figure find: a. the current in the 3.00 Omega resistor,b. the unknown emfs E_1 and E_2 and c the resistance R .

Find r, r', e delta for the case shown in figure