I JHA 45A 17. For the circuit shown in the figure the rms value of voltages across R and coil are E, and E,, respectively. R Lor 000 Resistor Coil e = E, sinot

For the circuit shown in the figure the rms value of voltage across R and coil are E_(1) and E_(2) respectively. The power (thermal) developed across the coil is

In the circuit shown, tp across the 2R resistor muhe voltage drost be

In the circuit shown, tp across the 2R resistor muhe voltage drost be

In the series L-C-R circuit shown in the figure, the rms voltage across the resistor and inductor are 400 V and 700 V respectively. If the applied voltage is E=500sqrt(2)sin(omega t) , then the peak voltage across the capacitor is

In the series L-C-R circuit shown in the figure, the rms voltage across the resistor and inductor are 400 V and 700 V respectively. If the applied voltage is E=500sqrt(2)sin(omega t) , then the peak voltage across the capacitor is

In the circuit, as shown in the figure, if the value of R.M.S current is 2.2 ampere, the power factor of the box is (E = 220 V)

In the circuit shown in figure find: a. the current in the 3.00 Omega resistor,b. the unknown emfs E_1 and E_2 and c the resistance R .

In the circuit shown in figure find: a. the current in the 3.00 Omega resistor,b. the unknown emfs E_1 and E_2 and c the resistance R .