The sum of series `(601)/(50) (1/(1+1^2+1^4)+2/(1+2^2+2^4)+3/(1+3^2+3^4)+...+24/(1+(24)^2+(24)^4))` is

The summation of series (601)/(5)sum_(r=1)^(24)(r)/(r^(4)+r^(2)+1) is

The sum to infinity of the series (1)/(2.4)+(1)/(4.6)+(1)/(6.8)+(1)/(8.10)+...... is

Find the sum of: 24 terms and n terms of 2 (1)/(2) , 3 (1)/(3) , 4 (1)/(6) ,5 ,......,

1+(1)/(2). (3)/(5) + (1.3)/(2.4) . (9)/(25)+(1.3.5)/(2.4.6).(27)/(125)+…...oo=

Locate the points: (1,1),(1,2),(1,3),(1,4) (2, 1),(2,2),(2,3),(2,4)(1,3),(2,3),(3,3),(4,3)(1,4),(2,4),(3,4),(4,4)

(1)/(1.3).(1)/(2)+(1)/(2.4).(1)/(2^(2))+(1)/(3.5).(1)/(2^(3))+....=

The rank of [(-1,2),(-2,4),(3,6)] is

The points (1,5) , (2,4) and (3,3) are