Home
Class 12
PHYSICS
Acceleration of a paritcle moving in x-y...

Acceleration of a paritcle moving in `x-y` plane varies with time t as. `vec(a) = (ti + 3T^(2)j)`.
Here a is in `m//s^(2)` and t in sec. At time `t = 0` particle is at rest origin. Mass of the particles is `1 kg`. Find the net work done on the particle in first `2 sec`.

Promotional Banner

Similar Questions

Explore conceptually related problems

A particle of mass 6 kg moves accordings to the law x=0.2 t^2-0.02 t^3 . Find the work done by the force in first 4 sec.

Acceleration of a particle in x-y plane varies with time as a=(2t hati+3t^2 hatj) m//s^2 At time t =0, velocity of particle is 2 m//s along positive x direction and particle starts from origin. Find velocity and coordinates of particle at t=1s.

Acceleration of a particle in x-y plane varies with time as a=(2t hati+3t^2 hatj) m//s^2 At time t =0, velocity of particle is 2 m//s along positive x direction and particle starts from origin. Find velocity and coordinates of particle at t=1s.

The coordinates of a particle moving in XY-plane vary with time as x= 4t^(2), y= 2t . The locus of the particle is a : -

The coordinates of a particle moving in XY-plane vary with time as x= 4t^(2), y= 2t . The locus of the particle is a : -

The speed of a particle moving in a circle of radius r=2m varies with time t as v=t^(2) , where t is in second and v in m//s . Find the radial, tangential and net acceleration at t=2s .

Position time graph of a particle of mass 2 kg is shown in figrure. Total work done on the particle from t=0 to t=4s is

Position time graph of a particle of mass 2 kg is shown in figrure. Total work done on the particle from t=0 to t=4s is

Position time graph of a particle of mass 2 kg is shown in figrure. Total work done on the particle from t=0 to t=4s is