If the roots of `(z-1)^n=i(z+1)^n` are plotted in an Argand plane, then prove that they are collinear.

If the roots of (z-1)^n=i(z+1)^n are plotted in ten Arg and plane, then prove that they are collinear.

The roots of (z-1)^n=i(z+1)^n are plotted on the argand plane they are

If the roots of (z-1)^(n)=i(z+1)^(n) are plotted on the argand plane, they are

If z^4= (z-1)^4 then the roots are represented in the Argand plane by the points that are

If z^4=(z-1)^4 , then the roots are represented in the Argand plane by the points that are:

Let A(z_1),B(z_2) and C(z_3) be the three points in Argands plane The point A B and C are collinear if

If the roots of (z-1)^(n)=2w(z+1)^(n) (where n>=3o* w complex cube root of unity are plotted in argand plane,these roots lie on

Prove that the equations , |(z-1)/(z+1)| = constant and amp ((z-1)/(z+1)) = constant on the argand plane represent the equations of the circle wich are orthogonal .

If |z-1|=1, where is a point on the argand plane, show that (z-2)/(z)=i tan (argz),where i=sqrt(-1).

, a point 'z' is equidistant from three distinct points z_(1),z_(2) and z_(3) in the Argand plane. If z,z_(1) and z_(2) are collinear, then arg (z(z_(3)-z_(1))/(z_(3)-z_(2))). Will be (z_(1),z_(2),z_(3)) are in anticlockwise sense).