[" If "y=y(x)" and it follows the relation "x cos y+y cos x=pi],[" then "y''(0)=]

If y=y(x) and it follows the relation e^(xy)+y cos x=2, then find (i)y'(0) and (ii) y(0)

If y = y(x) and it follows the relation e^(xy) + y cos x = 2 , then find (i) y'(0) and (ii) y"(0) .

If y = y(x) and it follows the relation e^(xy) + y cos x = 2 , then find (i) y'(0) and (ii) y"(0) .

If y = y(x) and it follows the relation e^(xy) + y cos x = 2 , then find (i) y'(0) and (ii) y"(0) .

If y=y(x) and it follows the relation e^(xy^(2))+y cos(x^(2))=5 then y'(0) is equal to

If x sin y+y cos x=pi , then the value of y''(0) is -

If y=y(x) is the solution of the equation e^(sin y) cos y""(dy)/(dx) +e^(sin y) cos x = cos x,y (0)=0, then 1+y ((pi)/(6)) +( sqrt(3))/(2) y((pi)/(3)) +(1)/( sqrt(2)) y((pi)/(4)) is equal to

If 0 le x, y le 2 pi "and cos"x + "cos" y = -2, " then "cos" (x+y)=