Two batteries of different emf and internal resistances connected in series with each other and with an external load resistor. The current reversed, the current becomes 1.0 A. the ratio of the emf of the two batteries is

Two batteries of difference emf's and internal resistance are connected in parallel to one another.

Four cells, each of emf E and internal resistance r, are connected in series across an external resistance reverse. Then, the current in the external circuit is

When two cells of different emf.s are connected in series to an external resistance the current is 5A. When the poles of one cell are interchanged, the current is 3A. The ratio of emf.s of two cell is

When two cells of different emf.s are connected in series to an external resistance the current is 5A. When the poles of one cell are interchanged, the current is 3A. The ratio of emf.s of two cell is

When a resistor of 20 Omega is connected in series with a battery, the current is 0.5 A. when a resistor of 10 Omega is connected the current becomes 0.8 A. calculate the emf and the internal resistance of the battery.

A battery of emf 12V and internal resistance 2Ω is connected with two resistors A and B of resistance 4Ω and 6Ω respectively joined in series. . The current i in the circuit is

Two batteries each of E and internal resistance r are connected turen by turn in series and in parallel, and areused to find current in an external resistance R . If the current in series is equal to that in parallel, the internal resistance of each battery is

A battery of emf 15 V and internal resistance of 4Omega is connected to a resistor. If the current in the circuit is 2A and the circuit is closed. Resistance of the resistor and terminal voltage of the battery will be

A battery of emf 15 V and internal resistance of 4Omega is connected to a resistor. If the current in the circuit is 2A and the circuit is closed. Resistance of the resistor and terminal voltage of the battery will be