(cos(pi+x)cos(-x))/(sin(pi-x)cos(pi/2-x)...

` (cos(pi+x)cos(-x))/(sin(pi-x)cos(pi/2-x))=cot^2x`

Verified by Experts

`L.H.S. = (cos(pi+x)cos(-x))/(sin(pi-x)cos(pi/2+x))`
`=((-cosx)(cosx))/(sinx(-sinx)) = (-cos^2x)/-sin^2x`
`=cot^2x = R.H.S.`

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