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यदि ax+by=1 और bx+ay=(2ab)/(a^(2)+b^(2))...

यदि `ax+by=1` और `bx+ay=(2ab)/(a^(2)+b^(2))` हो तो `(x^(2)+y^(2))(a^(2)+b^(2))` किसके बराबर है?

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If ax+by=1 and bx+ay=(2ab)/(a^(2)+b^(2)) then (x^(2)+y^(2))(a^(2)+b^(2)) is equal to

ax+by=1 bx+ay=2

ax+by=a+b bx+ay=b^2

(ax+by)^(2)+(bx-ay)^(2)

(ax+by)^(2)-(ay+bx)^(2)

2 (ax+by)^(2)-(bx+ay)^(2)

Solve for x and y: ax+by=1" and "bx+ay=(2ab)/(a^(2)+b^(2)) .

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}