[" 4.If functions "f(x)" and "g(x)" are defined on "R rarr R" such that "f(x)={[x+3,,,x in" rational "],[4x,,,x" eirrational "],[-x,,,x in" rational "]]

If the functions f(x) and g(x) are defined on R rarr R such that f(x) ={:{(0, x in " rational "),( x, x in " irrational ") :} g(x) ={:{(0, x in " irrational ") ,(x, x in " rational "):} then (f-g) (x) is

If the functions f(x) and g(x) are defined on R rarr R such that f(x)=(x+3,x in ratioal 4x,x in irrational,and g(x)=x+sqrt(5),x in irrational;-x,x in rational Then (f-g)(x) is

If the functions f(x) and g(x) are defined on R rarr R such that f(x)={0,x in retional and x,x in irrational ;g(x)={0,x in irratinal and x,x in rational then (f-g)(x) is

If the functions f(x) and g(x) are defined on R -> R such that f(x)={0, x in retional and x, x in irrational ; g(x)={0, x in irratinal and x,x in rational then (f-g)(x) is

the function f:R rarr R defined as f(x)=x^(3) is

Two functions f: R rarr R and g: R rarr R are defined by f(x) = {(0,x \ rational)(1 , x \ irrational),:}g(x)={(-1,x \ rational)(0 , x \irrational):} then g of e + fog(pi)

Two functions f:Rrarr R, g:R rarr R are defined as follows : f(x)={{:(0,"(x rational)"),(1,"(x irrational)"):}," " g(x)={{:(-1,"(x rational)"),(0,"(x irrational)"):} then (fog)(pi)+(gof)(e)=

Two functions f:Rrarr R, g:R rarr R are defined as follows : f(x)={{:(0,"(x rational)"),(1,"(x irrational)"):}," " g(x)={{:(-1,"(x rational)"),(0,"(x irrational)"):} then (fog)(pi)+(gof)(e)=