By using intergration prove that the area of a circle of radius r units is `pir^2` square units.

Prove that the area of the circle with radius r is pi r^2

Using lim_(theta -> 0) (sintheta/theta)=1 prove that the area of circle of radius R is piR^2 (Figure)

Area of a circle = 2pir^(2) .

Using ("lim")_(thetato0)(sintheta)/theta=1 prove that the area of circle of radius R is piR^2 (Figure)

The area of a square made in a circle of radius r is

What is the area of a circle inscribed in a square of side 'a' units?

Using lim_(theta -> 0) (sintheta/theta)=1 prove that the area of circle of radius R is piR^2

The maximum area of a rectangle that can be inscribeb in a circle of radius 2 units is square units )

Evaluate int_o^rsqrt(r^2-x^2) dx ,where r is a fixed positive number .Hence prove the area of the circle of radius r is pir^2