अवकल समीकरण `(tan^(-1)x-y)dx=(1+x^2)dy` को हल कीजिए |

tan^(-1)((dy)/(dx))=x+y

tan ^ (- 1) ((dy) / (dx)) = x + y

Solve: tan^-1(dy/dx)=x+y

Solve: tan^-1(dy/dx)=x+y

If y=tan^(-1)(x^3) then dy/dx=

if y=sec(tan^(-1)x)then(dy)/(dx) is

If y=tan^(-1)x ,then (dy)/(dx) is

If y = tan^(-1) ((2x)/(1-x^(2))) then dy/dx =

Solve the following differential equations (i) (1+x^(2)) (dy)/(dx) + y = e^(tan^(-1))x (ii) (1+x^(2))(dy)/(dx) + y = tan^(-1)x