7+27+777+n dig i6=(7)/(81)(10^(n+1)-9n-10)

Prove the following by the principle of mathematical induction: 7+77+777++777++ddot n-digits7=(7)/(81)(10^(n+1)-9n-10) for all n in NB.

If ninNN , then by principle of mathematical induction prove that, 7+77+777+ . . . to n terms =(7)/(81)(10^(n+1)-9n-10) .

By mathematical indcution prove that, 4+44+444+ . . . "to n terms "=(4)/(81)(10^(n+1)-9n-10) .

Prove the following by the principle of mathematical induction: 7+77+777++777++\ ddotn-d igi t s7=7/(81)(10^(n+1)-9n-10) for all n in N

Prove the following by the principle of mathematical induction: 7+77+777++777++\ ddotn-d igi t s7=7/(81)(10^(n+1)-9n-10) for all n in N

Prove the following by the principle of mathematical induction: 7+77+777+.....+777++\ ddotn-d igi t s7=7/(81)(10^(n+1)-9n-10) for all n in N Bdot

Prove by using the principal of mathematical inductions 4+ 44 +444+ ….+ 444…4 ( n digits ) = ( 4)/(81) (10 ^(n+1) - 9n -10)

Using mathematical induction show 7+77+777+......+n terms = 7/81(10^(n+1)-9n-10)

prove that 7 + 77 + 777 +...... + 777........._(n-digits) 7 = 7/81 (10^(n+1) - 9n - 10) for all n in N

prove that 7 + 77 + 777 +...... + 777........._(n-digits) 7 = 7/81 (10^(n+1) - 9n - 10) for all n in N