Home
Class 12
PHYSICS
[" (2) The motion of a particle is descr...

[" (2) The motion of a particle is described by "],[x=x_(0)(1-e^(-kt));t>=0,x_(0)>0,k>0." With what velocity "],[" does the particle start? "],[[" (a) "(x_(0))/(k)," (b) "x_(0)k," (c) "(k)/(x_(0))," (d) "2x_(0)k]]

Promotional Banner

Similar Questions

Explore conceptually related problems

The motion of a particle is described by x = x_o(1 - e^(-kt)) ,, t ge , x_o gt0, k gt 0. With what velocity does the particle start?

The motion of a particle is described by x = x_o(1 - e^(-kt)) ,, t ge , x_o gt0, k gt 0. With what velocity does the particle start?

A particle executes the motion described by x(t) = x_0 (1-e^(-gammat) , t le 0, x_0 > 0 . Where does the particle start and with what velocity?

A particle exceutes the motion describes by x(t)=x_(0)(1-e^(-gammat)),tge0,x_(0)0 . The maximum and minimum values of v(t) are

The position x of a particle at time t is given by x=(V_(0))/(a)(1-e^(-at)) , where V_(0) is constant and a gt 0 . The dimensions of V_(0) and a are

The acceleration of a particle is given as a = 3x^2 . At t = 0, v = 0, x = 0. The velocity at t = 2 sec will be-

The acceleration of a particle is given by a = 3t and at t = 0, v = 0, x = 0. The velocity and displacement at t = 2 sec will be-

The position x of a particle at time t is given by : x=(v_(0))/(a)(1-e^(-at)) where v_(0) is a constant and a>0. The dimensional formula of v_(0) and a is :