[y=tan^(-1)((a cos x-b sin x)/(b cos x+a sin x))," where "-(pi)/(2)-1]

If y = tan^(-1) ((a cos x - b sin x)/(b cos x + a sin x)) " then " (dy)/(dx) = ?

If y= tan ^(-1) ((a cos x- b sin x )/(b cos x + a sin x ) ) , then (dy)/(dx) is :

If y= tan^(-1)((a cos x-b sin x)/(b cos x+a sin x))" show that, " (dy)/(dx)= -1 .

Differentiate, tan^(-1) ((a cos x- b sin x)/(b cos x + a sin x)), (-pi)/(2) lt x lt (pi)/(2) and (a)/(b) tan x gt -1

simplify : tan^(-1) ""((a cos x- b sin x )/(b cos x + a sin x ) ) (- pi )/(2) lt x lt pi/2 , a/b tan x gt -1

Simplify tan^(-1)[(a cos x-b sin x)/(b cos x+a sin x)], if (a)/(b)tan x>-1

Find (dy)/(dx) in the following: y= tan^(-1) ((a cos x- b sin x)/(b cos x + a sin x))

"If "y=tan^(-1)((a cos x- b sin x)/(b cos x + a sin x)), (b/a)tanx lt 1"where "-(pi)/(2)ltxlt(pi)/(2)" then find "(dy)/(dx).