f(i)/kx(x-2)+6=0

Find the values of k for each of the following quadratic equations, so that they have two equal roots : (1) 2x^(2)+kx+3=0 (2) kx(x-2)+6=0

For equal root , kx (x-2) + 6 = 0 , the value of k is

Find the values of k for which the given quadratic equation has real and distinct roots: (i) kx^(2)+6x+1=0" "(ii)" "x^(2)-kx+9=0 (iii) 9x^(2)+3kx+4=0" "(iv)" "5x^(2)-kx+1=0

"If" kx (x -2) + 6 = 0 has equal roots then k =

Find the values of k for which the given equation has real roots: (i) kx^(2)-6x-2=0" "(ii)" "3x^(2)+2x+k=0" "(iii)" "2x^(2)+kx+2=0

Find the value(s) of k for which the given quadratic equations has real and distinct roots : (i) 2x^(2)+kx+4=0 (ii) 4x^(2)-3kx+1=0 (iii) kx^(2)+6x+1=0 (iv) x^(2)-kx+9=0

Find the value(s) of k for which the given quadratic equations has real and distinct roots : (i) 2x^(2)+kx+4=0 (ii) 4x^(2)-3kx+1=0 (iii) kx^(2)+6x+1=0 (iv) x^(2)-kx+9=0

If for f(x) = kx^(2) + 5x + 3, f'(2) = 6 , then k is equal to

If for f(x) = kx^(2) + 5x + 3, f'(2) = 6 , then k is equal to