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The period of sin^2theta is...

The period of `sin^2theta` is

A

`pi^2`

B

`pi`

C

`2pi`

D

`(pi)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

Since ,
`sin^2theta=(1-cos2theta)/(2)=(1)/(2)-(1)/(2)cos2theta`
`therefore` Period of `sin^2theta=(2pi)/(2)=pi`
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