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A man and his wife appear for an interview for two posts. The probability of the man's slection is 1/5 and that of his wife's slection is `1//7`. The probability that atleast one of them is selected , is

A

`(9)/(35)`

B

`(12)/(35)`

C

`(2)/(7)`

D

`(11)/(35)`

Text Solution

Verified by Experts

The correct Answer is:
D
`P(Acup B)=P(A)+P(B)-P(A cap B)=P(A)+P(B)-P(A)P(B)`
(`because` A and B are independent events)
`P(A cap B)=P(A).P(B)`
`=(1)/(5)+(1)/(7)-(1)/(35)=(11)/(35)`
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