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If in a triangle ABC, 3 sin A = 6 sin B...

If in a triangle `ABC, 3 sin A = 6 sin B=2sqrt3sin C`, then the angle A is

A

`0^(@)`

B

`30^@`

C

`60^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`because 3 sin A=6 B=2sqrt(3).sinC`
Dividing throughout by 6,
`rArr (sinA)/(2)=(sinB)/(1)=(sinc)/(sqrt(3))`
`rArr (a)/(2)=(b)/(1)=(c)/(sqrt(3))=K`
`therefore b^2+c^2=a^2`
`therefore angle A =90^@`
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