Figure shows the displacement time graphs of two simple harmonic motions I and II. From the graph it follows that

Options

A. curve I has same frequency as that of curve II
B. curve I has frequency twice that of curve II
C. curve I has frequency half that of curve II
D. curve I has frequency four times that of curve II

Answer

C

Explanation

Displacement (m)

From the graph
For curve I
Time period, `T_(1) = 8s`
Frequency `v_(1) = (1)/(T_(1)) = (1)/(8) Hz`
For curve II,
Time period `T_(2) = 4s`
Frequency `v_(2) = (1)/(T_(2)) = (1)/(4)Hz`
Their corresponding ratio
`(v_(1))/(v_(2)) = (1)/(2)` or `v_(1) = (1)/(2)v_(2)`