In the given circuit the potential at point B is zero, the potential at points A and D will be

Options

A. `V_(A) = 4 V, V_(D) = 9V`
B. `V_(A) = 3V,V_(D) = 4V`
C. `V_(A) = 9V, V_(D) = 3V`
D. `V_(A) = 4V, V_(D) = -3V`

Answer

D

Explanation

From the given circulit
`V_(A) - V_(B) = 2 xx 2 = 4V`
According to question `V_(B) =0`
Point D is connected to positive terminal of battery of emf 3V.
As, `V_(B) -V_(C) = 2xx 3 = 6V`
`therefore V_(D) - V_(C) = V_(D) - (-6) = 3V`
` rArr V_(D) = 3 - 6 = - 3V`