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Ionization potential of hydrogen atom is...

Ionization potential of hydrogen atom is `13.6 V`. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy `12.1 eV`. The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

A

1

B

2

C

3

D

4

Text Solution

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The correct Answer is:
C

Energy in exchited state
` =- 13.6 + 12.1 =- 1.5eV`
`therefore - (13.6)/(n^(2)) = - 1.5`
`therefore n = sqrt((13.6)/(1.5)) = 3`
Number of spectral lines `=(n(-1))/(2)`
` = (3(3-1))/(2) = 3`
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