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If the length of rod A is 3.25 pm 0.01 c...

If the length of rod A is 3.25 `pm` 0.01 cm and that of B is 4.19 `pm` 0.01 cm then the rod B is longer than rod A by

A

`(0.94 pm 0.00)cm`

B

`(0.94 pm 0.01)cm`

C

`(0.94 pm 0.02)cm`

D

`(0.95 pm 0.005 ) cm`

Text Solution

Verified by Experts

The correct Answer is:
C

Given , length of rod A,
`L_(A) = 3.25 pm0.001`
length of rod `B, L_(B) = 4.19 pm 0.01`
Then , the rod B is longer than rod A by length
`Delta l = L_(B) - L_(A)`
`rArr" "Delta = (4.19 pm 0.01) - (3.25 pm 0.01)`
`Delta = (0.94 pm 0.02) cm`
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