A 50 ohm galvanometer gets full scale deflection when a current of 0.01 A passes through the coil. When it is converted to a 10 A ammeter, the shunt resistance is

Options

A. `0.01Omega`
B. `0.05Omega`
C. `200 Omega`
D. `5000Omega`

Answer

B

Explanation

Let, the shunt resistance be S.

Given
`l = 10A , l_(g) = 0.01A, R_(g) = 50 Omega`
From the figure
`l_(g),R_(g) = (l-l_(g)) S`
`rArr 0.01 xx 50 = (10-0.01)S`
r `" 'S = (0.5)/(9.99) = 0.05 Omega`