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The equation of second degree x^2+2sqrt2...

The equation of second degree `x^2+2sqrt2x+2y^2+4x+4sqrt2y+1=0` represents a pair of straight lines.The distance between them is a. 4 b. `4/sqrt3` c. 2 d. `2sqrt3`

A

1 units

B

2 units

C

3 units

D

4 units

Text Solution

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The correct Answer is:
B
Here, `h = sqrrt(2) , g =2 , a = 1 , c = 1,b =2 , f = 2sqrt(2)`
`therefore ` Distance `= 2 sqrt((g^(2) - ac)/(a(a+b)))`
` = 2sqrt((4-1)/(1(1+2))) = 2` units
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