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Write the value of the derivative of `f(x)=|x-1|+|x-3|` at `x=2` .

A

2

B

1

C

0

D

`-2`

Text Solution

Verified by Experts

The correct Answer is:
C

Let `f(x) = |x-1| +|x-3|`
`={{:(,x-1+x-3, x ge 3),(,x-1+3-x, 1 le x lt 3),(,1-x+3-x, x le 1):}`
`{{:(,2x -4, x ge 3),(,2,1le xle3),(,4-2x, x lt 1):}`
At x = 2 funtion is
`f(x) = 2`
`rArr f(x) = 0`
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