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A 500 kg car takes a round turn of radi...

A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km/hr . The centripetal force is

A

250N

B

750N

C

1000N

D

1200N

Text Solution

Verified by Experts

The correct Answer is:
C
The centripetal force required for a car (mass m) to take a sharp turn of radius r with velocity v is `F=(mv)^(2)/(F)`
Given, m=500g
`v=36km//h=36xx(5)/(18)=10m//s,r=50m`
Hence, `F=(500xx(10)^(2))/(50)=1000N`
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