The moment of inertia of a uniform circular disc of radius `R` and mass `M` about an axis passing from the edge of the disc and normal to the disc is.

Options

A. `MR^(2)`
B. `(2)/(5)MR^(2)`
C. `(3)/(2)MR^(2)`
D. `(1)/(2)MR^(2)`

Answer

C

Explanation

The moment of inertia about on axis passing through centre of mass of disc and perpendicular to its plane is
`I_(CM)=(1)/(2)MR^(2)`
where M is the mass of disc and R its radius. According to theorem of parallel axis, moment of inertia of circular disc about an axis touching the disc at its diameter and normal to the disc is
`I=I_(CM)+MR^(2)`
`=(1)/(2)MR^(2)+MR^(2)`
`=(3)/(2)MR^(2)`