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Two dice are rolled one after the other....

Two dice are rolled one after the other.The probability that the number on the first dice is smaller than that of the number on second dice is-

A

`(1)/(2)`

B

`(7)/(18)`

C

`(3)/(4)`

D

`(5)/(12)`

Text Solution

Verified by Experts

The correct Answer is:
B

Let `A_(i)`= Event of getting a number I on first die `B_(i)`= Event of getting a number more than I or second die.
The required probability
`=P(A_(1) cap B_(1))+P(A_(2) cap B_(2))+P(A_(3) cap B_(3)) +P(A_(4) cap B_(4))+P(A_(S) capB_(S))`
`=underset(i=1)overset(5)sum P(A_(i) cap B)==underset(i=1)overset(5)sum P(A_(i))P(B_(i))` [`therefore A_(i), B_(i)` are independent events)
`=(1)/(6)[P(B_(i))+P(B_(2))+......+P(B_(i))]`
`=(1)/(6)[(5)/(6)+(4)/(6)+(3)/(6)+(2)/(6)+(1)/(6)]=(5)/(12)`
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