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When acetamide is treated with Br(2) and...

When acetamide is treated with `Br_(2)` and caustic soda, the paroduct formed is

A

N-bromamide

B

Bromoacetic acid

C

methanamine

D

ethanamine

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The correct Answer is:
C

Amides reacti with bromine and caustic soda to give their corresponding primary amines. Thus, acetamide gives methanamine. This reaction is know as Hofmann's bromadide, degradation reaction.
`H_(3)-underset("acetamide")overset(O)overset(||)C-NH_(2)+Br _(2)+4KOH overset(343K) to +2BKr_(2)CO_(3)+underset("methanamine")(H_(3)C-NH_(2))+2H_(2)O`
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