If `Delta` E is the heat of reactin for
`C_(2)H_(5)OH(l)+3O_(2)(g) to 2CO_(2)(g)+3H_(2)O(l)` at constant volume the `DeltaH` (heat of reaction at constant pressure), at constant temperature is

Options

A. `DeltaH=DeltaE+RT`
B. `DeltaH=DeltaE-RT`
C. `DeltaH=DeltaE-RT`
D. `DeltaH=DeltaE-2RT`

Answer

B

Explanation

We know, half, `Delta H= Delta E+ Delta nRT`
where,
`Deltan` = number of moles of gasesous products - number of moles of gaseous reactants
`=2-3=-1`
So, `Delta H= Delta E-RT`