The number of ethers possible with the molecular formula `C_(4)H_(10)O` is.

Options

A. one
B. two
C. three
D. four

Answer

C

Explanation

Isomers of `C_(4)H_(10)O` are as follows
(i) `H_(3)C-CH_(2)- underset("butanol-1")(CH_(2))-CH_(2)-OH,`(ii) `H_(3)C-underset("butaanol-2")underset(OH) underset(|)(CH)-CH_(2)-CH_(3)`
`(iii) (CH_(3))-underset("2-methyl propanol-1")overset(CH_(3))overset(|)(CH)-CH_(2)-OH`
(iv) `H_(3)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-OH`

Hence, there isomeric ethers are possible.