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Solubility of Ca(OH)(2) is s mol L^(-1)....

Solubility of `Ca(OH)_(2)` is s mol `L^(-1).` The solubility product `(K_(sp))` under the same condition is

A

`4s^(3)`

B

`3s^(4)`

C

`4s^(2)`

D

`s^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Ca(OH) hArr Ca^(2+)+2OH^(-)`
`K_(sp)=[Ca^(2+)][OH^(-)]^(2)`
`=(s)(2s)^((2)=4s^(2)`
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